SOLUTION: A broker invested 10,000$. Part of the money was invested at 8% per year and the remainder at 10% per year. if the investment earned 872 in 1 year, how much was invested at each am

SOLUTION: A broker invested 10,000$. Part of the money was invested at 8% per year and the remainder at 10% per year. if the investment earned 872 in 1 year, how much was invested at each am

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Question 312958: A broker invested 10,000$. Part of the money was invested at 8% per year and the remainder at 10% per year. if the investment earned 872 in 1 year, how much was invested at each amount?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.10x+.08(10,000-x)=872
.10x+800-.08x=872
.02x=872-800
.02x=72
x=72/.02
x=3,600 Invested @ 10%
10,000-3,600=6,400 Invested @ 8%
Proof:
.10*3,600+.08*6,400=872
360+512=872
872=872
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