SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
Log On
Question 310328: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
You can put this solution on YOUR website! Two cyclists start biking from a trail's start 3 hours apart.
The second cyclist travels at 10 miles per hour and starts 3 hours after the
first cyclist who is traveling at 6 miles per hour.
How much time will pass before the second cyclist catches up with the first
from the time the second cyclist started biking?
:
Let t = travel time of the 2nd cyclist
then
(t+3) = travel time of the 1st cyclist
:
When the 2nd cyclist catches the 1st, they will have traveled the same distance
Write a dist equation: dist = speed * time
:
2nd cyclist dist = 1st cyclist dist
10t = 6(t+3)
10t = 6t + 18
10t - 6t = 18
4t = 18
t =
t = 4.5 hrs travel time for the 2nd cyclist to catch the 1st
:
:
Check solution by finding the distance of each (should be the same)
1st cyclist travel time = 7.5 hrs
6*7.5 = 45 mi
10*4.5 = 45 mi
