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a passenger train and a freight train start at the same time from station that
are 405 miles apart and travel toward each other.
the rate of the passenger train is twice the rate of the freight train.
in 3 hrs, the trains will pass each other, find the rate of each.
formulate chart, equation, and solve
Let r = rate of the freight train
2r = rate of the pass train
When the trains meet the total dist of the two trains = 405 mi
Freight's dist + pass dist = 405 mi
3r + 3(2r) = 405
3r + 6r = 405
9r = 405
r = 45 mph is the freight
2(45) = 90 mph is pass
3(45) = 135
3(90) = 270