# SOLUTION: a passenger train and a freight train start at the same time from station that are 405 miles apart and travel toward each other. the rate of the passenger train is twice the rate o

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 Question 309887: a passenger train and a freight train start at the same time from station that are 405 miles apart and travel toward each other. the rate of the passenger train is twice the rate of the freight train. in 3 hrs, the trains will pass each other, find the rate of each. formulate chart, equation, and solveAnswer by ankor@dixie-net.com(15656)   (Show Source): You can put this solution on YOUR website!a passenger train and a freight train start at the same time from station that are 405 miles apart and travel toward each other. the rate of the passenger train is twice the rate of the freight train. in 3 hrs, the trains will pass each other, find the rate of each. formulate chart, equation, and solve : Let r = rate of the freight train then 2r = rate of the pass train : When the trains meet the total dist of the two trains = 405 mi : Freight's dist + pass dist = 405 mi 3r + 3(2r) = 405 3r + 6r = 405 9r = 405 r = r = 45 mph is the freight then 2(45) = 90 mph is pass : : Check solution 3(45) = 135 3(90) = 270 ------------ total: 405