SOLUTION: Lewiston and Vermillionville are 192 miles apart. A car leaves Lewiston traveling toward Vermillionville. Another car leaves Vermillionville at same time traveling toward Lewis
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Question 309199: Lewiston and Vermillionville are 192 miles apart. A car leaves Lewiston traveling toward Vermillionville. Another car leaves Vermillionville at same time traveling toward Lewiston. The car leaving Lewiston averages 10 miles per hour faster that the other, and they meet after 1 hour and 36 minuts. What are the average speeds of the cars?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Since the cars are travelling toward each other, the exact same time would elapse if one of the cars wasn't moving at all and the other car was travelling the sum of the two speeds.
Distance equals rate times time, so rate is equal to distance divided by time. 6 minutes is 0.1 hour. So 36 minutes 6 times 6 minutes so it is 6 times 0.1 hour is 0.6 hour. So 1 hour 36 minutes is 1.6 hours.
So the sum of the two cars speeds is 120 miles per hour.
Let 
represent the slower car's speed and then 
represents the faster car's speed. And we now know that:
The slower car goes 55 mph, and the faster one goes 65.
John
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