SOLUTION: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water?

Question 29959: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water?
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
Let the speed of the boat in still water be x
Against = -
"back again" = +
5hours and 20 minutes =5 1/3--->16/3

Equation;

Expand:

Multiply the whole equation by 3 to remove the fraction:

Hence, the speed of the boat is 7.8mph in the still water.
Paul.
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