SOLUTION: one plane flies at a ground speed 50 miles per hour faster than another. on a particular flight, the faster plane requires 3 hours and the slower one 3 hours and 30 minutes. what i

Question 297103: one plane flies at a ground speed 50 miles per hour faster than another. on a particular flight, the faster plane requires 3 hours and the slower one 3 hours and 30 minutes. what is the distance of the flight?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
Speed of the slower plane = x miles per hour.
Speed of the faster plane = (x+50) miles per hour.

Rate * Time = Distance.

Faster plane equation becomes:

(x+50) * 3 = D

Slower plane equation becomes:

x * 3.5 = D

Since they both equal D, then they both equal each other and we get:

(x+50) * 3 = x * 3.5

Simplify to get:

3*x + 150 = 3.5*x

Subtract 3*x from both sides of the equation to get:

.5*x = 150

Divide both sides of the equation by .5 to get:

x = 300

The slower plane is flying at 300 miles per hour.

The faster plane is traveling at 350 miles per hour.

the equation for the faster plane becomes:

350 * 3 = D = 1050 miles.

The equation for the slower plane becomes:

300 * 3.5 = D = 1050 miles.

the distance is the same in both equations as it should be.

The distance is 1050 miles.

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