SOLUTION: After being shot into the air, the height of a rocket is h=80t-16t^2 where h is the height above the ground, in feet, after t seconds. After how many seconds will the rocket be at

Question 29661: After being shot into the air, the height of a rocket is h=80t-16t^2 where h is the height above the ground, in feet, after t seconds. After how many seconds will the rocket be at a height of 96 feet?
thank you for the help
Answer by ikdeep(226) (Show Source): You can put this solution on YOUR website!
h=80t-16t^2 .......
we are to find t ot time after 96 feet
so the requried equation =
96 = 80t - 16t^2 ....
hope this will help you ,,,
if you are not able to solve it further also,,please let me know...

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