SOLUTION: A and B start their journey from a point X. If A travels north and B travels west such that after a time T the distance between A and B is 6 times more than the distance travelled

Question 295199: A and B start their journey from a point X. If A travels north and B travels west such that after a time T the distance between A and B is 6 times more than the distance travelled by the slower walker and the distance travelled by the faster walker is 3 times that of the other. Find the distance travelled by the slower walker.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
We are dealing with a right triangle here.
The distance between them is the hypotenuse c
and the distances walked are the legs.
so we have
slower =s
faster =f and
distance =c
c=6*s
f=3*s
s^2+f^2=c^2
We have three equations in three unknowns
By substitution we have one equation with one unknown.
s^2+(3*s)^2=(6*s)^2
s^2+9s*2=36s^2
10s^2=36s^2
The only possible solution is 0
Double check the word problem.
Something is odd about the way it says "6 times more than the distance traveled by the slower walker." It seems like there should be a number in there.
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