SOLUTION: Two Joggers, one averaging 9 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 15 minutes after the other jogger.

Question 293807: Two Joggers, one averaging 9 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 15 minutes after the other jogger. Find the distance of the run.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two Joggers,
one averaging 9 mph and one averaging 5 mph, start from a designated initial point.
The slower jogger arrives at the end of the run 15 minutes after the other jogger.
Find the distance of the run.
:
let t = the time of the faster jogger
then
(t+.25) = time of the slower jogger
:
We know they both travel the same distance
:
Change 15 min to .25 hr
:
Write a distance equation
:
9t = 5(t+.25)
:
9t = 5t + 1.25
:
9t - 5t = 1.25
:
4t = 1.25
t =
t = .3125 hrs
:
Find the distance
.3125 * 9 = 2.8125 miles
check the distance
(.3125+.25) * 5 = 2.8125 miles
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