SOLUTION: two racers 15 miles apart start at the same time traveling in the same direction. after 6 hrs, the faster racer overtakes the slower. if they had traveled toward each other they wo

Algebra.Com
Question 292418: two racers 15 miles apart start at the same time traveling in the same direction. after 6 hrs, the faster racer overtakes the slower. if they had traveled toward each other they would have met after 2 hrs. find the rate of each
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
6x+15=6y
2x+2y=15
x=5/2 y=5

RELATED QUESTIONS

two cyclists who are 15 km apart start at the same time traveling the same direction.... (answered by TimothyLamb)
Two cyclists begin traveling in the same direction on the same bike path. One travels... (answered by checkley77)
Two brothers start at same time from two places 20 kms apart. If they walk in same... (answered by josmiceli)
Two buses leave the station at the same time. one traveled west at a certain speed and... (answered by josgarithmetic)
Two cars start at the same place and time and travel in opposite directions. One car is (answered by stanbon,solver91311)
Two bicyclists start at the same time at a given point and travel in the same direction... (answered by checkley77)
two cars start at the same time at a given point and travel in the same direction at a... (answered by Alan3354)
Two trucks leave the same place at the same time, traveling in opposite directions. One... (answered by josmiceli)
Two cars, one traveling 8 miles per hour faster than the other, start at the same time... (answered by JulietG)