SOLUTION: charles started a trip by car averaging 49 miles per hour samantha started a trip by car from the same place and in the same direction averaging 51 miles per hour if samantha left

Question 291683: charles started a trip by car averaging 49 miles per hour samantha started a trip by car from the same place and in the same direction averaging 51 miles per hour if samantha left 24 mintues later how long will it take samantha to catch up to charles
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
charles started a trip by car averaging 49 miles per hour
samantha started a trip by car from the same place and in the same direction averaging 51 miles per hour if samantha left 24 mintues later how long will it take samantha to catch up to charles
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Charles DATA:
rate = 49 mph; time = x hrs ; distance = 49x miles
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Samantha DATA:
rate = 51 mph; time = (x-24/60) ; distance = 51x - 20.4 miles
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Equation:
distance = distance
49x = 51x-20.4
-2x = -20.4
x = 10.2 hrs
----
x-(24/60) = 10.2-0.4 = 9.8 hrs = 9 hrs 48 minutes
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Cheers,
Stan H.
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