SOLUTION: Two jets leave Dever at 9:00am one flying east at a speed 50 mph greater than the other,which is flying west. At 11:00 am the planes are 2500 miles apart. Find each of their speeds

Question 29091: Two jets leave Dever at 9:00am one flying east at a speed 50 mph greater than the other,which is flying west. At 11:00 am the planes are 2500 miles apart. Find each of their speeds and distances.
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Your question: Two jets leave Dever at 9:00am one flying east at a speed 50 mph greater than the other,which is flying west. At 11:00 am the planes are 2500 miles apart. Find each of their speeds and distances.
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Lets define a variable first.
we will say that x is equal to the mph of the slower plane
since the faster plane was going 50 mph faster than the slower plane, x+50
In all, it took two hours to travel 2500 miles
So the equation would look like this:
2(x)+2(x+50)=2500------solve for x
2x+2x+100=2500-------combine and subtract 100
4x=2400------divide by 4
x=600
so the slower plane is going 600mph
Since the faster plane's equation is x+50, the faster plane is going 650mph!
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