SOLUTION: At 7:00 am Joe stats jogging at 6mph. At 7:30 am Ken starts after him. How fast must ken run in order to catch him at 8:00 am? How far did each jog?
Algebra.Com
Question 29089: At 7:00 am Joe stats jogging at 6mph. At 7:30 am Ken starts after him. How fast must ken run in order to catch him at 8:00 am? How far did each jog?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
JOE RUNS 6MPH FOR 1 HOUR AND COVERS 6 MILES
KEN RUNS X MPH FOR .5 HOURS AND COVERS 6 MILES THEREFORE .5X=6 OR X=6/.5 OR
X=12MPH
RELATED QUESTIONS
at 7:00 AM joe starts jogging at 6 mi/h. at 7:10 am ken starts off after him. how fast... (answered by Alan3354)
at 7:00 am joe starts jogging at 6mi/h . At 7:10 Ken starts off after him. How fast must... (answered by lwsshak3,mananth)
at 7:00 a.m joe starts jogging at 6 mi/h. at 7:30 ken starts off after him. how fast must (answered by richwmiller,ankor@dixie-net.com)
At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast (answered by ankor@dixie-net.com)
At 7:00 a.m., Joe starts jogging at 6 mph. At 7:10 a.m., Ken starts off after him. How... (answered by ankor@dixie-net.com)
At 7 am Joe starts jogging at 6mi/hr. At 7:10 am Ken starts off after him. How fast... (answered by mananth)
At 7:00 A.M. Joe starts jogging at 6mi/h. At 7:10 A.M. Ken starts off after him. How fast (answered by College Student)
Can you please help me with this word problem: At 7:00 am Joe starts jogging at 6mi/h. At (answered by checkley77)
At 7 a.m. Joe starts jogging at 6 mi/h. At 7:10 a.m. Ken starts off after him. How fast... (answered by josgarithmetic,ikleyn,MathTherapy)