SOLUTION: A 150 mile trip is driven at R miles per hour. The same trip would take 2 hours less if you increase the speed by 20 mph. What is R? I have tried R=150/t R=150/t-2 (150/t+2=150/

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Question 28932: A 150 mile trip is driven at R miles per hour. The same trip would take 2 hours less if you increase the speed by 20 mph. What is R? I have tried R=150/t
R=150/t-2 (150/t+2=150/t-2).t(t-1)= 150t-150t+2t2-2t= t2-t-150=0 = (t+2)(t+75)and that is as far as I get because I know that that is not right.
Thank you for your help. These always put me in a tail spin. Cheryl Vogel

Found 2 solutions by Paul, stanbon:
Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!
let the normal speed be
If increased by 20 the speed will be x+20
Subtract the increase speed by the normal speed respect to the distance = time.

Equation:






a=1, b=20, c=-1500



Simplfy that and you get 2 solutions:

x=-50 and x=30

Remove the negative

Hence, the normal speed (R) is 30mph.
Paul.


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
original data: 150=Rt. So, t=150/R
Modified time and rate result in the following:
150=(R+20)(t-2)
Substitue for "t" to get:
150=(R+20)[(150/R)-2]
150=150-2R+3000/R-40
0=-2R^2+3000-40R
0=2R^2+40R-3000
0=R^2+20R-1500
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=6400 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 30, -50. Here's your graph:

Hope this helps.
Cheers,
Stan H.

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