SOLUTION: Bob travels on a train at 80 mph with a 30 minute layover halfway through the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles. Which method o

Question 288624: Bob travels on a train at 80 mph with a 30 minute layover halfway through the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles. Which method of transportation train or car allows Bob to arrive sooner at his destination?
Found 2 solutions by ankor@dixie-net.com, richwmiller:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Bob travels on a train at 80 mph with a 30 minute layover halfway through
the 156 mile trip at 8:00a.m. or by car traveling 55 mph at 8:00a.m. traveling 156 miles.
Which method of transportation train or car allows Bob to arrive sooner at his destination?
:
Write a time equation for each; time = dist/speed
:
Train: + .5 = 2.45 hrs
Car: = 2.84 hrs
:
Obviously, the train wins!
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
There really isn't enough info to decide the real answer.
Where is the car? Where is the train station?
by train
80x=156
x=(156/80)*60+30
147 minutes
2 hr 27 minutes
by car
55*t=156
t=156/55)
(156/55)*60=170.1=2 hr 50 minutes
that is only a matter of 23 minutes
How far away is the train station? How would he get there?

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