SOLUTION: tom leaves school on a bike going 10 mph. zeke leaves school 1 hour later going the same direction at a rate of 30 mph. how long before zeke overtakes tom?
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Question 286372: tom leaves school on a bike going 10 mph. zeke leaves school 1 hour later going the same direction at a rate of 30 mph. how long before zeke overtakes tom?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT
D=10T FOR TOM.
D=30(T-1) FOR ZEKE.
SET THESE 2 EQUATIONS EQUAL:
10T=30(T-1)
10T=30T-30
10T-30T=-30
-20T=-30
T=-30/-20
T=1.5 HOURS THEY WILL MEET.
PROOF:
10*1.5=30(1.5-1)
15=30*.5
15=15
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