You can
put this solution on YOUR website!Let x = Joe's speed in still water
Let y = speed of current
Since there are two things we are solving for, we are looking at a system of linear equations in two variables.
Against Current:
rate = x - y
time = 0.20
distance = 3
0.20(x - y) = 3
0.20x - 0.20y = 3...This is our first equation.
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With Current:
rate = x + y
time = 0.30
distance = 3
0.30(x + y) = 3
0.30x + 0.30y = 3...This is our second equation.
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Here they are together:
0.20x - 0.20y = 3
0.30x + 0.30y = 3
Can you finish now?
