SOLUTION: A man was cycling south wards at a speed of 10 miles / hr when he met another man who was cycling west wards at the speed of 11 miles / hr. How far apart they would be after a peri
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-> SOLUTION: A man was cycling south wards at a speed of 10 miles / hr when he met another man who was cycling west wards at the speed of 11 miles / hr. How far apart they would be after a peri
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Question 281857: A man was cycling south wards at a speed of 10 miles / hr when he met another man who was cycling west wards at the speed of 11 miles / hr. How far apart they would be after a period of 01 hour. Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! after one hour they will be diagonally apart . Like the hypotenuse of a right triangle.
the legs will be 11 and 10 since after one hour they would have traveled 11 and 10 miles repectively
10^2+11^2= hyp^2
sqrt 221 = hypotenuse
= 14.866 miles.
