SOLUTION: A guy on a bike leaves from point A going 18 MPH. One hour later a car leaves from the same point going 45 MPH. How long will it take for the car to catch the guy on the bike?

Question 278274: A guy on a bike leaves from point A going 18 MPH. One hour later a car leaves from the same point going 45 MPH. How long will it take for the car to catch the guy on the bike?
Found 2 solutions by rfer, Alan3354:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
18 mile lead
18/45=.4 hrs= 24 min
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A guy on a bike leaves from point A going 18 MPH. One hour later a car leaves from the same point going 45 MPH. How long will it take for the car to catch the guy on the bike?
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The bike is 18 miles ahead (and still moving at 18 mph)
The car gains on the bike at 27 mph (45-18)
18 miles/27 mph = 2/3 hours = 40 minutes.
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