SOLUTION: I need help with this question Jim made a 350 mile trip in his car at a certain speed. If he had gone 10 mph faster, he could have made the trip in one hour less time. Find hi

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Question 275068: I need help with this question
Jim made a 350 mile trip in his car at a certain speed. If he had gone 10 mph faster, he could have made the trip in one hour less time. Find his speed.

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Jim made a 350 mile trip in his car at a certain speed.
If he had gone 10 mph faster, he could have made the trip in one hour less time.
Find his speed.
:
Let s = his speed
then
(s+10) = the faster speed
:
Write a time equation; time = dist/speed
:
Actual time - faster time = 1 hr
= = 1
:
Multiply equation by s(s+10); results:
350(s+10) - 350s = s(s+10)
:
350s + 3500 - 350s = s^2 + 10s
combine and arrange as quadratic equation
s^2 + 10s - 3500 = 0
use the quadratic formula to find s

x = s; a=1; b=1-; c=-3500

:

:

the positive solution

:
s =
s = 54.37 mph is the actual speed
:
:
Check solution by finding the times
350/54.37 = 6.4 hrs
350/64.37 = 5.4 hrs, one hr difference

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