SOLUTION: a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?

Question 273949: a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a ship traveling east at 25mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 35mph. how long does it take the second ship to catch up to the first?
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1st ship DATA:
distance: x-10 mi ; rate = 25 mph ; time = d/r = (x-10)/25 hrs.
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2nd ship DATA:
distance = x miles ; rate = 35 mph ; time = d/r = x/35 hrs.
====================
Equation:
time = time
(x-10)/25 = x/35
35x - 350 = 25x
10x = 350
x = 35 miles
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time = x/35 = 35/35 = 1 hr
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Cheers,
Stan H.
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