SOLUTION: In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?

Question 273600: In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?
Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?
Let the quantity of 20% solution be x liters
12%------------------20%-------------------14% mix
6-------------------- x--------------------x+6 (quantity)
Form an equation with actual parts mixed
0.12*6 + 0.2 x = 0.14(x+6)
0.72+0.2x = 0.14x+0.84
0.2x-0.14x=0.84-0.72
0.06x=0.12
x=2 liters which is the quantity of 20% alcohol required

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
In words:
(liters of alcohol from 12% solution + liters of alcohol from 20% solution)/(total liters of final solution) = 14%
given:
= liters of alcohol in 12% solution
----------------------------------
Let = liters of 20% solution needed

2 liters of 20% solution are needed
check answer:

OK
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