You can
put this solution on YOUR website!You always have to read these carefully and sometimes restate them in a
way that makes it clearer.
the point where the train passes the car means they are dead even, neck and neck.
You start counting the time off there and you call the distance each has
travelled zero at that point.
The car can never catch up, let alone pass the faster train.
When is the slower car 20 miles behind the train?
distance = rate x time for both of them
r[c] = 65
r[t] = 80
You are going to put the same stopwatch on both train and car when the train
is 10 miles ahead, so
just call it t
The trains distance will be 20 miles ahead of the car's when you stop the time.
so
substitute
for d[c] in the equation for the train's distaince.
1.3 hours is 1 hour and 20 minutes
You can check this answer by plugging it back into the equations
Use 4/3 for that
it checks
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