SOLUTION: A car A left city X traveling 60 mph.2 hours later a car B leaves City X, traveling the same road at 70 mph. When will car B reach car A? How far will each car have traveled? I

Question 268701: A car A left city X traveling 60 mph.2 hours later a car B leaves City X, traveling the same road at 70 mph. When will car B reach car A? How far will each car have traveled?
I really need help putting this into an equation then I will be able to solve it myself.
Thanks!
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This is an RTD problem. Here is a table based on the given information
cars . . . . . . . . . rate . . . . . . . . .time . . . . . . . . distance
A. . . . . . . . . . . .60. . . . . . . . . . x . . . . . . . . . . . .60x
B. . . . . . . . . . . . 70 . . . . . . . . . .x -2 . . . . . . . . . 70x - 140
since the distances are equal, we get
60x = 70x - 140
subtract 70x to get
-10x = -140
x = 14
It will take 14 hours for B to reach A
60*14 = 840 miles
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