SOLUTION: Two buses leave the same city at the same time moving in opposite directions. One travels at a rate of 5 miles per hour faster than the other. After 3 hours they are 375 miles apar
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Question 268141: Two buses leave the same city at the same time moving in opposite directions. One travels at a rate of 5 miles per hour faster than the other. After 3 hours they are 375 miles apart. How far did each bus travel?
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Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
speed of slower bus =
speed of faster bus =
They are moving apart at their combined speeds, which are:
Let = distance slower bus has gone in mi
Let = distance faster bus has gone in mi
mi
Since
mi
mi
The slower bus went 180 mi, the faster went 195 mi
check answer:
OK
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let
represent the rate of the slower bus. Then the rate of the faster bus must be
.
Since the two buses are traveling in opposite directions, the total rate is the sum of the rates of the two vehicles, namely:
, or
Since distance equals rate times time:
Solve for
. The distance traveled by the slower bus is
. The distance traveled by the faster bus is
John

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