Question 265640: Here is my problem: Sarah went to Jen house at 10:00 with 40 mph.The distance from her house to Jen house is 221 miles. Later, at 12:00, Jen went to Sarah house at a speech of 54 mph.How many miles will Sarah meet Jen?
Not: This is all i have remember.This is one of problems on the test.
I just want to make sure I did it right.
Here is what i have done so far
R*T=D
Sarah 40 t 40t
Jen 54 2-t 54(2-t)
40t=54(2-t)
40t=100-54t
+54t +54t
94t=100
t=1/3/47
40*1/3/47=42/26/47
it was a multiple choice test. i put 140 miles.im not sure,i guess on this one
Answer by josmiceli(19441)   (Show Source):
| |
|
