SOLUTION: A driver travels 12 miles to work at a constant speed and travels the same distance home also at a constant speed. His speed on the trip home is 10 miles per hour faster than the t
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Question 262716: A driver travels 12 miles to work at a constant speed and travels the same distance home also at a constant speed. His speed on the trip home is 10 miles per hour faster than the trip to work and the total time for both trips is 1 hours. Find his speed on the way to work.
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
This is an RTD problem. Here is a table based on the given information:
Driver . . . . . . . .rate . . . . . . . . time . . . . . . . .distance
work. . . . . . . . . R. . . . . . . . . . . .T. . . . . . . . . . . .12 . .
home. . . . . . . . .R+10 . . . . . . . . 1-T. . . . . . . .. 12. . .
totals. . . . . . . . . . . . . . . . . . . . .1 . . . . . . . . . . . . . .
we have the equation
rt = d
solve this for t and we get
t = d/r
From above,
and
So,
The sum of the times = 1 hr, so
step 1 - multiply by the common denominator of R(R+10) to get
step 2 - distribute to get
step 3 - combine like terms on the left to get
step 4- setting = 0, we get
step 5 - factoring, we get
step 6 - solved for R we get
R = 20
or
R = -7
--
So, R = 20 mpg on the way to work
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