SOLUTION: Please help me solve this problem: Two cyclists, 30 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours late
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Question 261131: Please help me solve this problem: Two cyclists, 30 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Two cyclists, 30 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
The time they travel to meet is the same since they start at the same time. = 2
Let speed of one be x
The speed of the other will be 2x
The total distance traveled by both the sisters = 30 miles.
Distance travel by one sister = r * t = 2x
Distance traveled by other sister = 2*2x=4x
2x+4x=30
6x=30
X=5
The speeds are 5 and 10 mph
M Ananth ----------- mananth@hotmail.com
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