# SOLUTION: Could you please help me with this problem: The excursion boat "Holiday" travels 35 km upstream and then back again in 4hours and 48 minutes. If the speed on the "Holiday" in still

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 Question 26014: Could you please help me with this problem: The excursion boat "Holiday" travels 35 km upstream and then back again in 4hours and 48 minutes. If the speed on the "Holiday" in still water is 15 km/h, what is the speed of the current? Thank you.Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!4 hours and 48 minutes = 4.8hours Still water speed = 15 Speed with the current = 15+x Speed against the current = 15-x total distance == 35 Equation: 35[(15+x)+(15-x)]=4.8[(15+x)(15-x)] SIMPLIFY x=2.5 Hence, the speed of the current is 2.5km/h. Paul.