SOLUTION: Could you please help me with this problem: The excursion boat "Holiday" travels 35 km upstream and then back again in 4hours and 48 minutes. If the speed on the "Holiday" in still

Question 26014: Could you please help me with this problem: The excursion boat "Holiday" travels 35 km upstream and then back again in 4hours and 48 minutes. If the speed on the "Holiday" in still water is 15 km/h, what is the speed of the current?
Thank you.
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
4 hours and 48 minutes = 4.8hours
Still water speed = 15
Speed with the current = 15+x
Speed against the current = 15-x
total distance == 35
Equation:

35[(15+x)+(15-x)]=4.8[(15+x)(15-x)] SIMPLIFY

x=2.5

Hence, the speed of the current is 2.5km/h.
Paul.

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