You can
put this solution on YOUR website!Usual Flight Data:
distance=1400; rate=x mph; time=d/r=1400/x hrs.
Faster Flight Data:
distance=1400; rate=1.1xmph; time=d/r=1400/1.1x
EQUATION:
Usual time-Faster time= 2/3 hr
(1400/x) - (1400-1.1x)= 2/3
Divide by 1400 to get:
1/x - 1/1.1x =1/2100
(1.1x-x)/(1.1x^2)= 1/2100
0.1x/1.1x^2= 1/2100
0.1/1.1x=1/2100
1.1x=210
x=190.90 (usual speed of the plane)
Cheers,
Stan H.