SOLUTION: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after t

Question 259861: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet?
: Let d = distance traveled by the woman (from town B) Then (300-d) = distance traveled by the man (from town A)
: Change 15 min to .25 hrs
: Write a time equation: Time = dist/speed
Man's travel time = woman's travel time + 15 min (.25 hr)
300-d/120 = d/80 + 1/4
-5d=-540 thereore d=108.
They will meet 108km away from B Is that correct?

Found 2 solutions by ankor@dixie-net.com, dabanfield:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
That is correct, way to go!
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
First we need to find the time elapsed when they meet. We can then calculate the distance traveled by either party.
So let t be the time elapsed when they meet. Then they meet when the two of them together have covered 300 km:
120*t + 80*(t-.25) = 300
Solve for t then calculate the man's distance from A as 120*t.

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