SOLUTION: A truck traveling at a constant rate of 45 miles per hour leaves Albany. One hour later a car traveling at a constant rate of 60 miles per hour also leaves Albany traveling in the

Question 252992: A truck traveling at a constant rate of 45 miles per hour leaves Albany. One hour later a car traveling at a constant rate of 60 miles per hour also leaves Albany traveling in the same direction on the same highway. How long will it take for the car to catch up to the truck, if both vehicles continue in the same direction on the highway?
Found 2 solutions by ptaylor, Alan3354:
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let t=time that elapses before the car catches the truck(after the car leaves)
When the car leaves, the truck has travelled 45*1=45 mi
Total distance truck travels in t hours=45+45t
Total distance car travels in t hours=60t
When the above two distances are equal, the car will have caught up with the truck,so:
45+45t=60t subtract 45t from each side
45+45t-45t=60-45t collect like terms
45=15t
t=3 hours-------------------------ans
CK
distance truck travels:
45+3*45=180 mi
Distance car travels=3*60=180 mi
Hope this helps---ptaylor
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do these the easy way:
-------------------------
In 1 hour, the truck is 45 miles away.
The car gains on the truck at 15 mph (60-45)
45/15 = 3 hours.
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