SOLUTION: Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
following the same route, ran at 5.25 mph to meet her. How many minutes, after
10:00 am, did the two
Algebra.Com
Question 252246: Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
following the same route, ran at 5.25 mph to meet her. How many minutes, after
10:00 am, did the two friends meet?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
following the same route, ran at 5.25 mph to meet her. How many minutes, after
10:00 am, did the two friends meet?
.
Apply the distance formula:
d = rt
d is distance
r is rate or speed
t is time
.
Let x = minutes after 10 am when the two friends meet
then
1.5(x/60 + 1) = 5.25(x/60)
Multiplying both sides by 60:
1.5(x + 60) = 5.25x
1.5x + 90 = 5.25x
90 = 3.75x
24 minutes = x
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