# SOLUTION: There were 429 people at a play. Admission was \$8 dollars each for adults and \$4.50 each for children. The total receipts were \$2641. How man adults and how many children attended?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: There were 429 people at a play. Admission was \$8 dollars each for adults and \$4.50 each for children. The total receipts were \$2641. How man adults and how many children attended?      Log On

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 Click here to see ALL problems on Travel Word Problems Question 251535: There were 429 people at a play. Admission was \$8 dollars each for adults and \$4.50 each for children. The total receipts were \$2641. How man adults and how many children attended? Where did I go wrong ??? Adult tickets: x Adult cost per ticket: 8.00 total: 8.00x childrens tickets: (429-x) childs cost per ticket: 4.50 total: 4.50(429-x) 8.00x+4.50(429-x)=2641 8.00x+1930.5-4.50x=2641 3.50x+1930.5=2641 3.50x=710.50 x=203 adult tickets: 203 child's tickets: 4.50(428-203)= 1017 total=203+1017=1220 This answer does not appear to total up...can some one tell me where i went wrong please :) thanks!!Answer by richwmiller(9144)   (Show Source): You can put this solution on YOUR website!this is where you went wrong total=203+1017=1220 and child's tickets: 4.50(428-203)= 1017 It is 429 not 428 total=203+1017=1220 should be total=203+c=429 c is the number of children not the cost of the children's tickets The two equations you need are a=number of adults c= number of children a+c=429 8a+4.5c=2641