SOLUTION: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and Train B is traveling at 120 mph. Train A passes a station at 3:20 P.M. If
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Question 248437: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and Train B is traveling at 120 mph. Train A passes a station at 3:20 P.M. If Train B passes the same station at 3:32 P.M., at what time will Train B catch Train A?
thanks
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT
D=100T
D=120(T-.2)
100T=120(T-.2)
100T=120T-24
100T-120T=-24
-20T=-24
T=-24/-20
T=1.2 HOURS AFTER TRAIN A LEAVES THE STATION THEY WILL MEET.
3:20+1:12=4:32 HOUR OF THEIR MEETING.
PROOF:
100*1.2=120(1.2-.2)
120=120*1
120=120
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