You can
put this solution on YOUR website!Let speed of the boat in still water be "b".
Upstream Data:
rate = b - 3 ; time = 5 hrs.
Downstream Data:
rate = b + 3 ; time = 5/2 hrs.
EQUATION Data:
Distance up = distance down and d=rt
(b-3)5 = (b+3)(5/2)
Multiply thru by "2" to get:
10(b-3) = 5(b+3)
10b-30 = 5b+15
5b = 45
b = 9 mph (speed of boat in still water)
Cheers,
stan H