SOLUTION: I am stuck on this question I hope you can help Suppose that the kicker for the chargers has a punt that can be modeled by h(t)=-2t^2+200, where its height from the ground can b

Question 243019: I am stuck on this question I hope you can help
Suppose that the kicker for the chargers has a punt that can be modeled by h(t)=-2t^2+200, where its height from the ground can be found based on how many seconds (t) have passed since the kick. Given this how long will it take for the foot ball to hit the ground?
P.s. I can figure out to type in exponents so the 2t^2 is supposed to be 2t squared
Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h(t)=-2t^2+200
--------------
At t = 0, the ball is 200 feet up?
I think it's
h(t)=-2t^2+200t
----------------
It hits the ground when h(t) = 0
h(t)=-2t^2+200t = 0
2t^2 = 200t
t = 0 (at the start)
t = 100 (at impact)
-------------------
No units were given. 100 seconds is a long time, but the gravity is weak. Maybe this is on Phobos or Diemos.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Suppose that the kicker for the chargers has a punt that can be modeled by h(t)=-2t^2+200,
where its height from the ground can be found based on how many seconds (t) have passed since the kick.
Given this how long will it take for the foot ball to hit the ground?
:
this equation cannot be right, this one shows the height as 200 when t=0
:
Assume the equation is h(t) = -2t^2 + 20t
:
When the ball hits the ground, h(t) = 0, therefore
-2t^2 + 20t = 0
Factor out -2t, this also changes the signs
-2t(t - 10) = 0
t = +10 sec
:
looks like this:

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