SOLUTION: I need to solve the following word problem using the system of linear equations in two variables. The word problem I am having trouble with is: Traveling with the current, a can

Question 240512: I need to solve the following word problem using the system of linear equations in two variables. The word problem I am having trouble with is:
Traveling with the current, a canoe can go 48 miles in 4 hours. traveling against the current, it takes 6 hours to go the same distance. find the speed of the canoe in still water.
I came up with the following linear equations:
12=x+y for speed of canoe with current
8=x-y for speed of canoe against current
I solved for each variable and came up with x=10, y=2.
My question is which one is the correct answer for finding the speed of the canoe in still water? My thought is it is x=10.
Please help
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT OR R=D/T
R=48/4=12 MPH WITH THE CURRENT.
R=48/6=8 MPH AGAINST THE CURRENT
(12-8)/2=4/2=2 MPH IS THE RATE OF THE CURRENT.
PROOF:
12-2=10 MPH SPEED OF THE CANOE IN STILL WATER.
8+2=10 DITTO.
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