SOLUTION: Two cyclists, 95 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 4 hr later, at what average speed is each cyclist t

Question 238842: Two cyclists, 95 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 4 hr later, at what average speed is each cyclist traveling? (Round the answers to two decimal places.)
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
D=RT
95=(X+2X)4
95=3X*4
95=12X
X=95/12
X=7.91 MPH IS THE SLOWER SPEED RIDER.
2*7.91=15.83 MPH FOR THE FASTER RIDER.
PROOF
95=(7.91+15.83)4
95=23.74*4
95~95

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