SOLUTION: if train a leaves chicago station at 8 a.m. at 40 mph and train b leaves the same station at 9 a.m what time will they meet and how many miles will they have traveled?
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: if train a leaves chicago station at 8 a.m. at 40 mph and train b leaves the same station at 9 a.m what time will they meet and how many miles will they have traveled?
Log On
Question 234569: if train a leaves chicago station at 8 a.m. at 40 mph and train b leaves the same station at 9 a.m what time will they meet and how many miles will they have traveled?
You can put this solution on YOUR website! There is missing data here.
In order to answer this question, I need to know the miles per hour of train b.
Understand?
Please, type the entire question correctly.
==========================================
Thanks for providing the extra piece of information.
The equation is 40(x + 1) = 50x.
Solving the equation, I got x = 4.
The time for train a is x + 1 or 5 more than 8am taking us to 1pm.
The time for train b is x or 4 more than 9am taking us to 1pm.
They meet at 1pm.
=================================================================
The distance for train a is 40mph times 5 = 200 miles.
Of course, train b also travelled 200 miles because 50mph times 4 = 200 miles.