SOLUTION: O.K I'm lost here, and need help. From the book; It states I'll need to use the formula 4.9t^2 + vt = s. Approximately how far will an object fall in 13 seconds(t) when thrown

Question 233200: O.K I'm lost here, and need help.
From the book; It states I'll need to use the formula 4.9t^2 + vt = s.
Approximately how far will an object fall in 13 seconds(t) when thrown downward at an initial velocity of 10 meters per second(v) from a plane?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
From the book; It states I'll need to use the formula 4.9t^2 + vt = s.
Approximately how far will an object fall in 13 seconds(t) when thrown downward at an initial velocity of 10 meters per second(v) from a plane?
-------------------
s(t) = 4.9t^2 + 10t
s(13) = 4.9*169 + 130
s(13) = 958.1 meters

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