You can put this solution on YOUR website!
2 cars leave intersection, one travel east; other north.
When the car traveling east had gone 15 miles the distance between the cars was
5 miles more than the distance traveled by the car heading north, how far had
the north bound car traveled.
this is a right triangle problems a^2 + b^2 = c^2
Let a = 15; the distance by the Eastbound car
Let b = distance traveled by the Northbound car
The distance between the cars is the hypotenuse
"distance between the cars was 5 miles more than the distance traveled by
the car heading north,", therefore
c = b+5
15^2 + b^2 = (b+5)^2
FOIL the right side
225 + b^2 = b^2 + 10b + 25
Subtract b^2 from both sides
225 = 10b + 25
Subtract 25 from both sides
225 - 25 = 10b
200 = 10b
b = 20 miles the distance of he northbound car
See if this is true
15^2 + 20^2 = 25^2
225 + 400 = 625!
How about this? Did it make sense to you?