SOLUTION: Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State answer for both variables.
There were
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Question 230652: Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State answer for both variables.
There were 500 people at a play. The admission price was $2.00 for adults and $1.00 for children. The admission receipts were $690.00. How many adults and children attended?
Found 2 solutions by scott8148, rfer:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
"There were 500 people at a play" ___ a + c = 500
"$2.00 for adults and $1.00 for children. The admission receipts were $690.00" ___ 2a + c = 690
subtracting 1st eqn from 2nd eqn ___ a = 190
substituting ___ 190 + c = 500 ___ c = 310
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
a+c=500, c=500-a
2a+c=690
2a+500-a=690
a=190
c=500-190=310
-----------------
a=190*2=$380
c=310*1=$310
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