SOLUTION: Two families meet at a park for a picnic. At the end of the day, one family travels east at an average speed of 42 miles per hour, and the other family travels west at an average s
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Question 230635: Two families meet at a park for a picnic. At the end of the day, one family travels east at an average speed of 42 miles per hour, and the other family travels west at an average speed of 50 miles per hour. Both families have approximately 160 miles to travel.
(a) Find the time it takes each family to get home.
(b) Find the time that will have elapsed when they are 100 miles apart.
(c) Find the distance the eastbound family has to travel after the westbound family has arrived home.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Two families meet at a park for a picnic. At the end of the day, one family
travels east at an average speed of 42 miles per hour, and the other family travels west at an average speed of 50 miles per hour.
Both families have approximately 160 miles to travel.
:
(a) Find the time it takes each family to get home.
:
Time = dist/speed
Family A: = 3.8 hrs, 3 hrs 48.6 min
Family B: = 3.2 hrs, 3 hrs 12 min
:
(b) Find the time that will have elapsed when they are 100 miles apart.
:
Let t = travel time for this to be accomplished
Dist = speed*time
42t + 50t = 100
92t = 100
t =
t = 1.09 hrs; 1 hr 5.2 min
:
(c) Find the distance the eastbound family has to travel after the westbound family has arrived home.
:
Another dist equation,
(it took 3.2 hrs for B to get home, how far will A drive in that time?)
160 - 3.2(42) =
160 - 134.4 = 25.6 mi to go
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