SOLUTION: On the first part of a 317 mile trip, a sales person averaged 58 miles per hour. The sales person averaged only 52 miles per hour on the last part of the trip because of an increas
Algebra.Com
Question 230585: On the first part of a 317 mile trip, a sales person averaged 58 miles per hour. The sales person averaged only 52 miles per hour on the last part of the trip because of an increased volume of traffic. The total time of the trip was 5 hours and 45 minutes. Find the amount of time at each of the two speeds.
Found 2 solutions by drj, Stitch:
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
On the first part of a 317 mile trip, a sales person averaged 58 miles per hour. The sales person averaged only 52 miles per hour on the last part of the trip because of an increased volume of traffic. The total time of the trip was 5 hours and 45 minutes. Find the amount of time at each of the two speeds.
Step 1. distance = speed * time
Step 2. Let t be the time traveled in the first part of the trip
Step 3. Let 5.75-t be the time traveled in the second part of the trip since 5 hours and 45 minutes is equal to 5.75 and that .
Step 4. Let 58t be the distance traveled at 58 miles per hour.
Step 5. Let 52(5.750-t) be the distance traveled at 52 miles per hour.
Step 6. Then 58t+52(5.75-t)=317 since the total distance of the trip is 317 miles.
Step 7. Solving 58t+52(5.75-t)=317 leads to the following steps
Subtract 299 from both sides of the equation
Divide by 6 to both sides of the equation
and
Check distance traveled if equal to 317
which is a true statement
Step 8. ANSWER: The sales person traveled for 3 hours at 58 miles per hour and for 2 hours and 45 minutes (=2.75 hours) at 52 miles per hour.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
http://www.FreedomUniversity.TV
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Given: Miles Total (Mt) = 317mi, Time = 5h - 45min
Our first equation: 317mi = {X*58mi/h} + {Y*52mi/h}
I converted the minutes to hours:
5h 45min = 5.75h ((45m/(60m/h))=.75
Our second equation: 5.75h = X + Y
Solve the 2nd equation for X:
5.75 = X + Y (Subtract Y from both sides)
5.75 - Y = X
Substitute 5.75h - Y in for X in Equation 1:
317mi = {{5.75h - Y} * 58mi/h} + {Y * 52mi/h}
317mi = {5.75h * 58mi/h} - {Y * 58mi/h} + {Y * 52mi/h} Then simplify
317mi = 333.5mi - Y*6mi/h Then add Y*6mi/h and -317mi to both sides
Y*6mi/h = 333.5mi - 317mi
Y*6mi/h = 16.5mi Then divide both sides by 6mi/h
Y = 2.75h
Plug 2.75h in for Y in the second equation:
5.75h = X + Y
5.75h = X + 2.75 Subtract 2.75 from both sides
3h = X
RELATED QUESTIONS
On the first part of a 317-mile trip, a salesperson average 58 miles per hour. The... (answered by ankor@dixie-net.com)
I just need to figure out the formula to solve this problem. On the first part of a... (answered by ankor@dixie-net.com)
please help me solve this word problem:
On the first past of a 317-mile trip, a... (answered by scott8148,josmiceli,gonzo)
On the first part of a 317-mile trip, a salesman averaged 58 miles per hour. He averaged... (answered by ankor@dixie-net.com)
On the first part of a 363-mile trip, Emily averaged 58 miles per hour. Due to increased... (answered by nerdybill)
On the first part of a 317 mile trip, a salesperson averaged 58mph. He averaged only... (answered by mananth)
Question#1
Two planes leave an airport in England at approximately the same time and... (answered by josgarithmetic)
I can not come up with how to do the following, could you please please help me?
On the... (answered by nerdybill)
a cyclist traveled the first 12 miles of a 30 mile trip at an average speed of 15 miles... (answered by ankor@dixie-net.com)