You can
put this solution on YOUR website!NOTE: For more examples like this one "In Living Color" see my Lesson Plan "Population Growth" in the topic "Logarithm" in algebra.com.
P= 1350 in 1945 when t= -45 (45 years before 1990)
Divide both sides by 2500:
Take the ln of both sides:
Divide both sides by -45:

k = .0136930253 approximately.
If you have a graphing calculator, store that value, and then use the calculator to evaluate the following, when t= 20 (years from 1990 to 2010) and k is the value from the calculator above:

or
NOTE: This problem can also be solved by letting the initial population be 1350 in year 1945, letting P= 2500 when t=45 in 1990. The value of k is EXACTLY the same! Then, to find the population in the year 2010, using the initial population of 2500, use the value of t = 20 years from 1990 to 2010. The result is EXACTLY the same!! Try it!!
R^2 at SCC
P.S. Do I get THREE points for solving this same problem THREE times???