SOLUTION: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles

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Question 23047: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
6(t+3)=10t
6t+18=10t
18=4t
t=4.5
hence, 4.5hours will pass.