SOLUTION: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
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Question 23047: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
6(t+3)=10t
6t+18=10t
18=4t
t=4.5
hence, 4.5hours will pass.
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