SOLUTION: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together? I did not get the answer t

Question 22995: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
I did not get the answer to this problem, so if you could please give me some solutions.
Found 2 solutions by rapaljer, AnlytcPhil:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
If Sally can paint the house in 4 hours, then in 1 hour she can paint 1/4 of the house.
If John can paint the house in 6 hours, then in 1 hour he can paint 1/6 of the house.
Let x = number of hours it would take them together to paint the house, then working together, in 1 hour they can paint 1/x of the house.

The equation is this:

Multiply both sides by the LCD which is 12x:

= 2.4 hours

R^2 at SCC

Answer by AnlytcPhil(1806) (Show Source): You can put this solution on YOUR website!

If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together? I did not get the answer to this problem, so if you could please give me some solutions. Let x = the number of hours it will take them painting together Then their combined rate = (1 house)/(x hours) or 1/x house/hr >>...Sally can paint a house in 4 hours...<< Translation: Sally's rate is (1 house)/(4 hours) or 1/4 house/hr >>...John can paint the same house in 6 hour...<< Translation: John's rate is (1 house)/(6 hours) or 1/6 house/ hr To form the equation: Sally's rate + John's rate = their combined rate 1/4 + 1/6 = 1/x Can you solve that? (Hint: get LCD = 12x and multiply thru) Answer: 2.4 hours or 2 hours 24 minutes Edwin AnlytcPhil@aol.com

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